Question 29

waecmaths question: 

Number of goals

1

2

3

4

5

6

7

Number of teams

3

1

6

6

4

2

3

The table shows the distribution of goal scored by 25 teams in a football competition.

Find the probability that a team selected at random scored either 4 or 7 goals

Option A: 

$\tfrac{6}{25}$

Option B: 

$\tfrac{11}{25}$

Option C: 

$\tfrac{3}{5}$

Option D: 

$\tfrac{18}{25}$

waecmaths solution: 

$\Pr (\text{4 or 7 goals)}=\frac{6}{25}+\frac{3}{25}=\frac{9}{25}$

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