Question 50

Jambmaths question: 

A number is chosen at random from 10 to 30 inclusive, what is the probability that the number is divisible by 3

Option A: 

$\tfrac{1}{10}$

Option B: 

$\tfrac{1}{3}$

Option C: 

$\tfrac{3}{5}$

Option D: 

$\tfrac{2}{15}$

Jamb Maths Solution: 

Numbers divisible by 3 are 12, 15, 18, 21, 24, 27, 30

N(numbers divisible by 3) =7

N(numbers from 10 to 30 inclusive) = 21 

P(number divisible by 3) = $\frac{7}{ 21} =\frac{1}{3}$

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